A bag contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
Practice Questions
1 question
Q1
A bag contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
2/5
1/5
1/2
4/10
Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A bag contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
Solution: Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.
Steps: 8
Step 1: Count the number of white balls in the bag. There are 4 white balls.
Step 2: Count the number of black balls in the bag. There are 6 black balls.
Step 3: Add the number of white balls and black balls to find the total number of balls. Total balls = 4 + 6 = 10.
Step 4: Identify the event we are interested in. We want to find the probability of drawing a ball that is not black, which means it must be a white ball.
Step 5: The number of favorable outcomes (white balls) is 4.
Step 6: The total number of possible outcomes (total balls) is 10.
Step 7: Calculate the probability of drawing a white ball (not black) by dividing the number of white balls by the total number of balls. Probability = Number of white balls / Total balls = 4 / 10.
