Using the chain rule, f\'(x) = (1/(x^2 + 1)) * (2x) = 2x/(x^2 + 1).
If f(x) = ln(x^2 + 1), what is f'(x)?
Practice Questions
Q1
If f(x) = ln(x^2 + 1), what is f'(x)?
2x/(x^2 + 1)
1/(x^2 + 1)
2/(x^2 + 1)
x/(x^2 + 1)
Questions & Step-by-Step Solutions
If f(x) = ln(x^2 + 1), what is f'(x)?
Step 1: Identify the function f(x) = ln(x^2 + 1).
Step 2: Recognize that we need to find the derivative f'(x).
Step 3: Use the chain rule for differentiation. The chain rule states that if you have a function inside another function, you take the derivative of the outer function and multiply it by the derivative of the inner function.
Step 4: The outer function is ln(u), where u = x^2 + 1. The derivative of ln(u) is 1/u.
Step 5: The inner function is u = x^2 + 1. The derivative of u with respect to x is 2x.