Question: A projectile is launched with an initial velocity of 40 m/s at an angle of 30 degrees. What is the horizontal range of the projectile? (Take g = 10 m/s²)
Options:
Correct Answer: 200 m
Solution:
Range R = (u² * sin(2θ))/g = (40² * sin(60°))/10 = (1600 * √3/2)/10 = 80√3 m ≈ 138.56 m.