In a mixture of two liquids, if the first liquid is 20% concentrated and the second is 80% concentrated, what is the concentration of the mixture if equal volumes are mixed?
Practice Questions
1 question
Q1
In a mixture of two liquids, if the first liquid is 20% concentrated and the second is 80% concentrated, what is the concentration of the mixture if equal volumes are mixed?
50%
60%
70%
40%
The average concentration = (20% + 80%) / 2 = 50%.
Questions & Step-by-step Solutions
1 item
Q
Q: In a mixture of two liquids, if the first liquid is 20% concentrated and the second is 80% concentrated, what is the concentration of the mixture if equal volumes are mixed?
Solution: The average concentration = (20% + 80%) / 2 = 50%.
Steps: 5
Step 1: Identify the concentrations of the two liquids. The first liquid has a concentration of 20%, and the second liquid has a concentration of 80%.
Step 2: Since we are mixing equal volumes of both liquids, we will take the average of their concentrations.
