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In a mixture of two liquids, if the first liquid is 20% concentrated and the sec

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Question: In a mixture of two liquids, if the first liquid is 20% concentrated and the second is 80% concentrated, what is the concentration of the mixture if equal volumes are mixed?

Options:

  1. 50%
  2. 60%
  3. 70%
  4. 40%

Correct Answer: 60%

Solution: 

The average concentration = (20% + 80%) / 2 = 50%.

In a mixture of two liquids, if the first liquid is 20% concentrated and the sec

Practice Questions

Q1
In a mixture of two liquids, if the first liquid is 20% concentrated and the second is 80% concentrated, what is the concentration of the mixture if equal volumes are mixed?
  1. 50%
  2. 60%
  3. 70%
  4. 40%

Questions & Step-by-Step Solutions

In a mixture of two liquids, if the first liquid is 20% concentrated and the second is 80% concentrated, what is the concentration of the mixture if equal volumes are mixed?
  • Step 1: Identify the concentrations of the two liquids. The first liquid has a concentration of 20%, and the second liquid has a concentration of 80%.
  • Step 2: Since we are mixing equal volumes of both liquids, we will take the average of their concentrations.
  • Step 3: Add the concentrations together: 20% + 80% = 100%.
  • Step 4: Divide the total by 2 to find the average concentration: 100% / 2 = 50%.
  • Step 5: The concentration of the mixture is 50%.
  • Concentration of Mixtures – Understanding how to calculate the concentration of a mixture by averaging the concentrations of the individual components when equal volumes are mixed.
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