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In a Wheatstone bridge, if R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for t
In a Wheatstone bridge, if R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for the bridge to be balanced?
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Practice Questions
1 question
Q1
In a Wheatstone bridge, if R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for the bridge to be balanced?
30Ω
20Ω
15Ω
10Ω
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For balance, R1/R2 = R3/R4. Thus, 10/20 = 15/R4, giving R4 = 30Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: In a Wheatstone bridge, if R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for the bridge to be balanced?
Solution:
For balance, R1/R2 = R3/R4. Thus, 10/20 = 15/R4, giving R4 = 30Ω.
Steps: 7
Show Steps
Step 1: Write down the formula for a balanced Wheatstone bridge: R1/R2 = R3/R4.
Step 2: Substitute the known values into the formula: 10/20 = 15/R4.
Step 3: Simplify the left side of the equation: 10/20 equals 0.5.
Step 4: Now the equation looks like this: 0.5 = 15/R4.
Step 5: To find R4, cross-multiply: 0.5 * R4 = 15.
Step 6: Divide both sides by 0.5 to isolate R4: R4 = 15 / 0.5.
Step 7: Calculate R4: R4 = 30Ω.
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