In a Wheatstone bridge, if the resistance R2 is doubled, what effect does it have on the balance condition?
Practice Questions
1 question
Q1
In a Wheatstone bridge, if the resistance R2 is doubled, what effect does it have on the balance condition?
It remains balanced.
It becomes unbalanced.
It requires R4 to be halved.
It requires R1 to be doubled.
Doubling R2 will change the ratio R1/R2, thus unbalancing the bridge.
Questions & Step-by-step Solutions
1 item
Q
Q: In a Wheatstone bridge, if the resistance R2 is doubled, what effect does it have on the balance condition?
Solution: Doubling R2 will change the ratio R1/R2, thus unbalancing the bridge.
Steps: 7
Step 1: Understand what a Wheatstone bridge is. It is a circuit used to measure unknown resistances by balancing two legs of a bridge circuit.
Step 2: Identify the components of the Wheatstone bridge. It has four resistors: R1, R2, R3, and R4.
Step 3: Know the balance condition of the Wheatstone bridge. The bridge is balanced when the ratio of R1 to R2 is equal to the ratio of R3 to R4 (R1/R2 = R3/R4).
Step 4: Consider the effect of doubling R2. If R2 is doubled, it becomes 2R2.
Step 5: Calculate the new ratio. The new ratio of R1 to R2 is now R1/(2R2).
Step 6: Compare the new ratio with the original balance condition. Since R1/(2R2) is not equal to R3/R4 anymore, the bridge becomes unbalanced.
Step 7: Conclude that doubling R2 changes the balance condition of the Wheatstone bridge.
