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In a Wheatstone bridge, if R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω, what is the value of
In a Wheatstone bridge, if R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω, what is the value of R4 for the bridge to be balanced?
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Practice Questions
1 question
Q1
In a Wheatstone bridge, if R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω, what is the value of R4 for the bridge to be balanced?
7.5Ω
10Ω
12.5Ω
15Ω
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Using the balance condition R1/R2 = R3/R4, we have 5/10 = 15/x, solving gives x = 7.5Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: In a Wheatstone bridge, if R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω, what is the value of R4 for the bridge to be balanced?
Solution:
Using the balance condition R1/R2 = R3/R4, we have 5/10 = 15/x, solving gives x = 7.5Ω.
Steps: 8
Show Steps
Step 1: Write down the balance condition for a Wheatstone bridge, which is R1/R2 = R3/R4.
Step 2: Substitute the known values into the equation: 5/10 = 15/R4.
Step 3: Simplify the left side of the equation: 5/10 simplifies to 1/2.
Step 4: Now the equation looks like this: 1/2 = 15/R4.
Step 5: Cross-multiply to eliminate the fraction: 1 * R4 = 2 * 15.
Step 6: Calculate the right side: 2 * 15 = 30, so R4 = 30.
Step 7: To find R4, we need to divide 30 by 2: R4 = 30 / 2 = 15.
Step 8: Therefore, R4 = 7.5Ω.
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