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If the resistances in a Wheatstone bridge are R1 = 20Ω, R2 = 30Ω, and R3 = 10Ω,
If the resistances in a Wheatstone bridge are R1 = 20Ω, R2 = 30Ω, and R3 = 10Ω, what is the value of R4 for the bridge to be balanced?
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Practice Questions
1 question
Q1
If the resistances in a Wheatstone bridge are R1 = 20Ω, R2 = 30Ω, and R3 = 10Ω, what is the value of R4 for the bridge to be balanced?
15Ω
20Ω
25Ω
30Ω
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Using the balance condition R1/R2 = R3/R4, we have 20/30 = 10/x, solving gives x = 20Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: If the resistances in a Wheatstone bridge are R1 = 20Ω, R2 = 30Ω, and R3 = 10Ω, what is the value of R4 for the bridge to be balanced?
Solution:
Using the balance condition R1/R2 = R3/R4, we have 20/30 = 10/x, solving gives x = 20Ω.
Steps: 8
Show Steps
Step 1: Write down the resistances given in the problem: R1 = 20Ω, R2 = 30Ω, R3 = 10Ω.
Step 2: Understand the balance condition for a Wheatstone bridge, which is R1/R2 = R3/R4.
Step 3: Substitute the known values into the balance condition: 20/30 = 10/R4.
Step 4: Cross-multiply to eliminate the fraction: 20 * R4 = 30 * 10.
Step 5: Calculate the right side: 30 * 10 = 300.
Step 6: Now you have the equation: 20 * R4 = 300.
Step 7: To find R4, divide both sides by 20: R4 = 300 / 20.
Step 8: Calculate the value: R4 = 15Ω.
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