A box contains 10 balls, of which 4 are red and 6 are blue. If one ball is drawn, what is the probability that it is not red?

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Q: A box contains 10 balls, of which 4 are red and 6 are blue. If one ball is drawn, what is the probability that it is not red?

Solution: Probability of not red = Number of non-red balls / Total balls = 6/10 = 3/5.

Steps: 7

Step 1: Identify the total number of balls in the box. There are 10 balls.
Step 2: Identify how many of those balls are red. There are 4 red balls.
Step 3: Calculate the number of non-red balls. Since there are 10 balls total and 4 are red, the number of non-red balls is 10 - 4 = 6.
Step 4: Write down the formula for probability. Probability of an event = (Number of favorable outcomes) / (Total outcomes).
Step 5: Substitute the values into the formula. The number of non-red balls is 6 and the total number of balls is 10.
Step 6: Calculate the probability. Probability of not red = 6 / 10.
Step 7: Simplify the fraction. 6 / 10 can be simplified to 3 / 5.