If R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω in a Wheatstone bridge, what is the value of

If R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω in a Wheatstone bridge, what is the value of R4 for balance?

If R1 = 5Ω, R2 = 10Ω, and R3 = 15Ω in a Wheatstone bridge, what is the value of R4 for balance?

Correct Answer: 30Ω

Step 1: Identify the values of the resistors given in the problem. R1 = 5Ω, R2 = 10Ω, R3 = 15Ω.
Step 2: Write down the balance condition for a Wheatstone bridge, which is R1/R2 = R3/R4.
Step 3: Rearrange the balance condition to solve for R4. This gives us R4 = (R2 * R3) / R1.
Step 4: Substitute the values of R2, R3, and R1 into the equation. So, R4 = (10 * 15) / 5.
Step 5: Calculate the multiplication in the numerator: 10 * 15 = 150.
Step 6: Divide the result by R1: 150 / 5 = 30.
Step 7: Conclude that the value of R4 for balance is 30Ω.

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