In a Wheatstone bridge, if the supply voltage is 12V and the bridge is balanced, what is the voltage across each arm?

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Q: In a Wheatstone bridge, if the supply voltage is 12V and the bridge is balanced, what is the voltage across each arm?

Solution: In a balanced Wheatstone bridge, the voltage divides equally across the two arms, so each arm would have 6V if the total is 12V.

Steps: 6

Step 1: Understand that a Wheatstone bridge has four resistors arranged in a diamond shape with a voltage supply connected across it.
Step 2: Know that when the bridge is balanced, the voltage across the two arms (each containing two resistors) is equal.
Step 3: Identify the total supply voltage, which is given as 12V.
Step 4: Since the bridge is balanced, the total voltage (12V) divides equally between the two arms.
Step 5: Calculate the voltage across each arm by dividing the total voltage by 2: 12V / 2 = 6V.
Step 6: Conclude that the voltage across each arm of the balanced Wheatstone bridge is 6V.