A pendulum swings to and fro. If the length of the pendulum is 1 m, what is the

₹0.0

Question: A pendulum swings to and fro. If the length of the pendulum is 1 m, what is the time period of the pendulum? (Take g = 10 m/s²)

Options:

Correct Answer: 2 s

Solution:

Time period T = 2π√(l/g) = 2π√(1/10) = 2π/√10 ≈ 2 s.

A pendulum swings to and fro. If the length of the pendulum is 1 m, what is the time period of the pendulum? (Take g = 10 m/s²)

A pendulum swings to and fro. If the length of the pendulum is 1 m, what is the time period of the pendulum? (Take g = 10 m/s²)

Step 1: Identify the formula for the time period of a pendulum, which is T = 2π√(l/g).
Step 2: Determine the length of the pendulum (l). In this case, l = 1 m.
Step 3: Identify the value of g (acceleration due to gravity). Here, g = 10 m/s².
Step 4: Substitute the values of l and g into the formula: T = 2π√(1/10).
Step 5: Calculate the value inside the square root: 1/10 = 0.1.
Step 6: Find the square root of 0.1: √0.1 ≈ 0.316.
Step 7: Multiply by 2π: T ≈ 2π * 0.316.
Step 8: Calculate 2π * 0.316 to get the approximate time period: T ≈ 2 s.

Pendulum Motion – The time period of a simple pendulum is determined by its length and the acceleration due to gravity.
Formula Application – Understanding how to apply the formula T = 2π√(l/g) correctly.