A mixture contains 25% of substance A and 75% of substance B. If the total weigh

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Question: A mixture contains 25% of substance A and 75% of substance B. If the total weight of the mixture is 200 grams, how much of substance B is present?

Options:

150 grams
175 grams
100 grams
125 grams

Correct Answer: 150 grams

Solution:

Amount of substance B = 75% of 200 grams = 0.75 * 200 = 150 grams.

A mixture contains 25% of substance A and 75% of substance B. If the total weigh

Practice Questions

A mixture contains 25% of substance A and 75% of substance B. If the total weight of the mixture is 200 grams, how much of substance B is present?

150 grams
175 grams
100 grams
125 grams

Questions & Step-by-Step Solutions

A mixture contains 25% of substance A and 75% of substance B. If the total weight of the mixture is 200 grams, how much of substance B is present?

Step 1: Understand that the mixture is made up of two substances: A and B.
Step 2: Note the percentages of each substance in the mixture: 25% is substance A and 75% is substance B.
Step 3: Identify the total weight of the mixture, which is given as 200 grams.
Step 4: To find the amount of substance B, calculate 75% of the total weight (200 grams).
Step 5: Convert the percentage to a decimal: 75% = 0.75.
Step 6: Multiply the decimal by the total weight: 0.75 * 200 grams.
Step 7: Perform the multiplication: 0.75 * 200 = 150 grams.
Step 8: Conclude that there are 150 grams of substance B in the mixture.

Percentage Calculation – Understanding how to calculate a percentage of a total amount.
Mixture Composition – Interpreting the composition of a mixture based on given percentages.

A mixture contains 25% of substance A and 75% of substance B. If the total weigh

What’s inside this PDF?

A mixture contains 25% of substance A and 75% of substance B. If the total weigh

Practice Questions

Questions & Step-by-Step Solutions

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