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In a mixture of two liquids A and B, if the ratio of A to B is 3:2, what is the
In a mixture of two liquids A and B, if the ratio of A to B is 3:2, what is the percentage of liquid A in the mixture?
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In a mixture of two liquids A and B, if the ratio of A to B is 3:2, what is the percentage of liquid A in the mixture?
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The total parts in the mixture = 3 + 2 = 5. The percentage of A = (3/5) * 100 = 60%.
Questions & Step-by-step Solutions
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Q
Q: In a mixture of two liquids A and B, if the ratio of A to B is 3:2, what is the percentage of liquid A in the mixture?
Solution:
The total parts in the mixture = 3 + 2 = 5. The percentage of A = (3/5) * 100 = 60%.
Steps: 5
Show Steps
Step 1: Identify the ratio of liquid A to liquid B, which is given as 3:2.
Step 2: Add the parts of the ratio together: 3 (for A) + 2 (for B) = 5 total parts.
Step 3: To find the percentage of liquid A, divide the part of A (which is 3) by the total parts (which is 5): 3 / 5.
Step 4: Multiply the result from Step 3 by 100 to convert it to a percentage: (3 / 5) * 100.
Step 5: Calculate the final result: (3 / 5) * 100 = 60%.
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