If the first term of an arithmetic progression is 7 and the last term is 37, wit

₹0.0

Question: If the first term of an arithmetic progression is 7 and the last term is 37, with a total of 16 terms, what is the common difference?

Options:

Correct Answer: 2

Solution:

Using the formula for the last term, l = a + (n-1)d, we have 37 = 7 + (16-1)d. Solving gives d = 2.

If the first term of an arithmetic progression is 7 and the last term is 37, with a total of 16 terms, what is the common difference?

If the first term of an arithmetic progression is 7 and the last term is 37, with a total of 16 terms, what is the common difference?

Step 1: Identify the first term (a) of the arithmetic progression, which is given as 7.
Step 2: Identify the last term (l) of the arithmetic progression, which is given as 37.
Step 3: Identify the total number of terms (n) in the arithmetic progression, which is given as 16.
Step 4: Use the formula for the last term of an arithmetic progression: l = a + (n-1)d.
Step 5: Substitute the known values into the formula: 37 = 7 + (16-1)d.
Step 6: Simplify the equation: 37 = 7 + 15d.
Step 7: Subtract 7 from both sides to isolate the term with d: 37 - 7 = 15d.
Step 8: Calculate the left side: 30 = 15d.
Step 9: Divide both sides by 15 to solve for d: d = 30 / 15.
Step 10: Calculate the value of d: d = 2.

Arithmetic Progression – An arithmetic progression (AP) is a sequence of numbers in which the difference between consecutive terms is constant.
Formula for the Last Term – The last term of an arithmetic progression can be calculated using the formula l = a + (n-1)d, where l is the last term, a is the first term, n is the number of terms, and d is the common difference.