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In a league of 5 teams, each team plays every other team twice. How many total m

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Question: In a league of 5 teams, each team plays every other team twice. How many total matches are played?

Options:

  1. 20
  2. 10
  3. 15
  4. 25

Correct Answer: 20

Solution:

Each team plays 4 other teams twice, so total matches = 5 * 4 / 2 * 2 = 20.

In a league of 5 teams, each team plays every other team twice. How many total m

Practice Questions

Q1
In a league of 5 teams, each team plays every other team twice. How many total matches are played?
  1. 20
  2. 10
  3. 15
  4. 25

Questions & Step-by-Step Solutions

In a league of 5 teams, each team plays every other team twice. How many total matches are played?
  • Step 1: Identify the number of teams in the league. There are 5 teams.
  • Step 2: Each team plays every other team. Since there are 5 teams, each team plays against 4 other teams.
  • Step 3: Each match between two teams is played twice (home and away). So, for each pair of teams, there are 2 matches.
  • Step 4: Calculate the total number of unique pairs of teams. The formula for this is (number of teams * (number of teams - 1)) / 2. Here, it is (5 * 4) / 2 = 10 pairs.
  • Step 5: Since each pair of teams plays 2 matches, multiply the number of pairs by 2. So, total matches = 10 pairs * 2 matches = 20 matches.
  • Combinatorial Counting – Understanding how to count the number of matches in a round-robin tournament format.
  • Multiplication and Division – Applying multiplication to calculate total matches and division to avoid double counting.
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