What is the condition for a Wheatstone bridge to be in equilibrium?

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Question: What is the condition for a Wheatstone bridge to be in equilibrium?

Options:

R1/R2 = R3/R4
R1 + R2 = R3 + R4
R1 - R2 = R3 - R4
R1 * R3 = R2 * R4

Correct Answer: R1/R2 = R3/R4

Solution:

In a Wheatstone bridge, the bridge is in equilibrium when the ratio of the resistances in one branch is equal to the ratio in the other branch, i.e., R1/R2 = R3/R4.

What is the condition for a Wheatstone bridge to be in equilibrium?

Practice Questions

What is the condition for a Wheatstone bridge to be in equilibrium?

R1/R2 = R3/R4
R1 + R2 = R3 + R4
R1 - R2 = R3 - R4
R1 * R3 = R2 * R4

Questions & Step-by-Step Solutions

What is the condition for a Wheatstone bridge to be in equilibrium?

Correct Answer: R1/R2 = R3/R4

Step 1: Understand that a Wheatstone bridge has four resistors arranged in a diamond shape.
Step 2: Identify the resistors: R1 and R2 are in one branch, and R3 and R4 are in the other branch.
Step 3: Know that for the bridge to be in equilibrium, the voltage across the middle (where the bridge connects) must be zero.
Step 4: This zero voltage condition occurs when the ratio of the resistances in one branch (R1/R2) is equal to the ratio in the other branch (R3/R4).
Step 5: Write the condition mathematically: R1/R2 = R3/R4.

Wheatstone Bridge Equilibrium Condition – The condition for equilibrium in a Wheatstone bridge is that the ratio of the resistances in one branch (R1/R2) must equal the ratio in the other branch (R3/R4).

What is the condition for a Wheatstone bridge to be in equilibrium?

What’s inside this PDF?

What is the condition for a Wheatstone bridge to be in equilibrium?

Practice Questions

Questions & Step-by-Step Solutions

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