What is the condition for a Wheatstone bridge to be in equilibrium?
Practice Questions
1 question
Q1
What is the condition for a Wheatstone bridge to be in equilibrium?
R1/R2 = R3/R4
R1 + R2 = R3 + R4
R1 - R2 = R3 - R4
R1 * R3 = R2 * R4
In a Wheatstone bridge, the bridge is in equilibrium when the ratio of the resistances in one branch is equal to the ratio in the other branch, i.e., R1/R2 = R3/R4.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the condition for a Wheatstone bridge to be in equilibrium?
Solution: In a Wheatstone bridge, the bridge is in equilibrium when the ratio of the resistances in one branch is equal to the ratio in the other branch, i.e., R1/R2 = R3/R4.
Steps: 5
Step 1: Understand that a Wheatstone bridge has four resistors arranged in a diamond shape.
Step 2: Identify the resistors: R1 and R2 are in one branch, and R3 and R4 are in the other branch.
Step 3: Know that for the bridge to be in equilibrium, the voltage across the middle (where the bridge connects) must be zero.
Step 4: This zero voltage condition occurs when the ratio of the resistances in one branch (R1/R2) is equal to the ratio in the other branch (R3/R4).
Step 5: Write the condition mathematically: R1/R2 = R3/R4.
