What is the condition for a Wheatstone bridge to be in equilibrium?

Practice Questions

Q1
What is the condition for a Wheatstone bridge to be in equilibrium?
  1. R1/R2 = R3/R4
  2. R1 + R2 = R3 + R4
  3. R1 - R2 = R3 - R4
  4. R1 * R3 = R2 * R4

Questions & Step-by-Step Solutions

What is the condition for a Wheatstone bridge to be in equilibrium?
Correct Answer: R1/R2 = R3/R4
  • Step 1: Understand that a Wheatstone bridge has four resistors arranged in a diamond shape.
  • Step 2: Identify the resistors: R1 and R2 are in one branch, and R3 and R4 are in the other branch.
  • Step 3: Know that for the bridge to be in equilibrium, the voltage across the middle (where the bridge connects) must be zero.
  • Step 4: This zero voltage condition occurs when the ratio of the resistances in one branch (R1/R2) is equal to the ratio in the other branch (R3/R4).
  • Step 5: Write the condition mathematically: R1/R2 = R3/R4.
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