The magnitude of the vector A = 4i - 3j + 12k is:

Practice Questions

Q1
The magnitude of the vector A = 4i - 3j + 12k is:
  1. 13
  2. 14
  3. 15
  4. 16

Questions & Step-by-Step Solutions

The magnitude of the vector A = 4i - 3j + 12k is:
  • Step 1: Identify the components of the vector A. The vector A is given as 4i - 3j + 12k. This means the components are: A_x = 4, A_y = -3, and A_z = 12.
  • Step 2: Square each of the components. Calculate 4^2, (-3)^2, and 12^2. This gives us: 4^2 = 16, (-3)^2 = 9, and 12^2 = 144.
  • Step 3: Add the squared values together. Add 16 + 9 + 144 to get 169.
  • Step 4: Take the square root of the sum. Calculate √169, which equals 13.
  • Step 5: The magnitude of the vector A is 13.
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