The magnitude of the vector A = 4i - 3j + 12k is:

Practice Questions

1 question
Q1
The magnitude of the vector A = 4i - 3j + 12k is:
  1. 13
  2. 14
  3. 15
  4. 16

Questions & Step-by-step Solutions

1 item
Q
Q: The magnitude of the vector A = 4i - 3j + 12k is:
Solution: Magnitude |A| = √(4^2 + (-3)^2 + 12^2) = √(16 + 9 + 144) = √169 = 13.
Steps: 5

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