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Find the minimum value of the function f(x) = 3x^2 - 12x + 9. (2022)

Practice Questions

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Find the minimum value of the function f(x) = 3x^2 - 12x + 9. (2022)
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Questions & Step-by-step Solutions

1 item
Q
Q: Find the minimum value of the function f(x) = 3x^2 - 12x + 9. (2022)
Solution: The minimum occurs at x = -b/(2a) = 12/(2*3) = 2. f(2) = 3(2^2) - 12(2) + 9 = 3.
Steps: 0

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