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For the quadratic equation x^2 + 6x + k = 0 to have real roots, what must be the condition on k? (2020)

Practice Questions

1 question
Q1
For the quadratic equation x^2 + 6x + k = 0 to have real roots, what must be the condition on k? (2020)
  1. k < 9
  2. k = 9
  3. k > 9
  4. k ≤ 9

Questions & Step-by-step Solutions

1 item
Q
Q: For the quadratic equation x^2 + 6x + k = 0 to have real roots, what must be the condition on k? (2020)
Solution: The discriminant must be non-negative: 6^2 - 4(1)(k) ≥ 0, which gives k ≤ 9.
Steps: 0

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