For the quadratic equation 2x^2 + 4x - 6 = 0, what is the value of the discrimin
Practice Questions
Q1
For the quadratic equation 2x^2 + 4x - 6 = 0, what is the value of the discriminant? (2020)
16
4
0
36
Questions & Step-by-Step Solutions
For the quadratic equation 2x^2 + 4x - 6 = 0, what is the value of the discriminant? (2020)
Step 1: Identify the coefficients a, b, and c from the quadratic equation 2x^2 + 4x - 6 = 0. Here, a = 2, b = 4, and c = -6.
Step 2: Write the formula for the discriminant, which is D = b^2 - 4ac.
Step 3: Substitute the values of a, b, and c into the formula. This gives us D = 4^2 - 4(2)(-6).
Step 4: Calculate 4^2, which is 16.
Step 5: Calculate 4(2)(-6). First, multiply 4 and 2 to get 8, then multiply 8 and -6 to get -48. Since we have a negative sign, it becomes +48.
Step 6: Now, add the results from Step 4 and Step 5: 16 + 48 = 64.
Step 7: The value of the discriminant D is 64.
Discriminant of a Quadratic Equation – The discriminant is a value that determines the nature of the roots of a quadratic equation, calculated using the formula D = b^2 - 4ac.