For the quadratic equation 2x^2 + 4x - 6 = 0, what is the value of the discrimin

Practice Questions

Q1
For the quadratic equation 2x^2 + 4x - 6 = 0, what is the value of the discriminant? (2020)
  1. 16
  2. 4
  3. 0
  4. 36

Questions & Step-by-Step Solutions

For the quadratic equation 2x^2 + 4x - 6 = 0, what is the value of the discriminant? (2020)
  • Step 1: Identify the coefficients a, b, and c from the quadratic equation 2x^2 + 4x - 6 = 0. Here, a = 2, b = 4, and c = -6.
  • Step 2: Write the formula for the discriminant, which is D = b^2 - 4ac.
  • Step 3: Substitute the values of a, b, and c into the formula. This gives us D = 4^2 - 4(2)(-6).
  • Step 4: Calculate 4^2, which is 16.
  • Step 5: Calculate 4(2)(-6). First, multiply 4 and 2 to get 8, then multiply 8 and -6 to get -48. Since we have a negative sign, it becomes +48.
  • Step 6: Now, add the results from Step 4 and Step 5: 16 + 48 = 64.
  • Step 7: The value of the discriminant D is 64.
  • Discriminant of a Quadratic Equation – The discriminant is a value that determines the nature of the roots of a quadratic equation, calculated using the formula D = b^2 - 4ac.
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