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If a mixture contains 40% alcohol and 60% water, how much water is present in 15

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Question: If a mixture contains 40% alcohol and 60% water, how much water is present in 15 liters of the mixture?

Options:

  1. 6 liters
  2. 9 liters
  3. 7 liters
  4. 8 liters

Correct Answer: 9 liters

Solution: 

60% of 15 liters is 0.6 * 15 = 9 liters of water.

If a mixture contains 40% alcohol and 60% water, how much water is present in 15

Practice Questions

Q1
If a mixture contains 40% alcohol and 60% water, how much water is present in 15 liters of the mixture?
  1. 6 liters
  2. 9 liters
  3. 7 liters
  4. 8 liters

Questions & Step-by-Step Solutions

If a mixture contains 40% alcohol and 60% water, how much water is present in 15 liters of the mixture?
  • Step 1: Understand that the mixture is made up of 40% alcohol and 60% water.
  • Step 2: Know that we need to find out how much water is in 15 liters of this mixture.
  • Step 3: Calculate 60% of 15 liters to find the amount of water.
  • Step 4: Convert 60% to a decimal, which is 0.6.
  • Step 5: Multiply 0.6 by 15 liters: 0.6 * 15 = 9 liters.
  • Step 6: Conclude that there are 9 liters of water in the mixture.
  • Percentage Calculation – Understanding how to calculate a percentage of a total quantity.
  • Mixture Composition – Recognizing the components of a mixture and their respective proportions.
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