In an arithmetic progression, if the 1st term is 4 and the 6th term is 24, what

Practice Questions

Q1
In an arithmetic progression, if the 1st term is 4 and the 6th term is 24, what is the common difference?
  1. 4
  2. 5
  3. 6
  4. 7

Questions & Step-by-Step Solutions

In an arithmetic progression, if the 1st term is 4 and the 6th term is 24, what is the common difference?
  • Step 1: Identify the first term of the arithmetic progression, which is given as 4.
  • Step 2: Identify the sixth term of the arithmetic progression, which is given as 24.
  • Step 3: Recall the formula for the nth term of an arithmetic progression: nth term = first term + (n-1) * common difference.
  • Step 4: For the sixth term (n=6), the formula becomes: 6th term = 4 + (6-1) * d.
  • Step 5: Substitute the known values into the equation: 24 = 4 + 5d.
  • Step 6: Simplify the equation: 24 - 4 = 5d, which gives 20 = 5d.
  • Step 7: Solve for d by dividing both sides by 5: d = 20 / 5.
  • Step 8: Calculate the value of d: d = 4.
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