In a circuit, if the voltage is increased from 5V to 15V while the resistance remains constant at 5 ohms, what is the change in current?

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Q: In a circuit, if the voltage is increased from 5V to 15V while the resistance remains constant at 5 ohms, what is the change in current?

Solution: Initial current I1 = 5V / 5Ω = 1 A; Final current I2 = 15V / 5Ω = 3 A; Change in current = I2 - I1 = 3 A - 1 A = 2 A.

Steps: 12

Step 1: Identify the initial voltage, which is 5V.
Step 2: Identify the final voltage, which is 15V.
Step 3: Identify the resistance, which is constant at 5 ohms.
Step 4: Use Ohm's Law (I = V / R) to calculate the initial current (I1).
Step 5: Substitute the initial voltage and resistance into the formula: I1 = 5V / 5Ω.
Step 6: Calculate I1, which equals 1 A.
Step 7: Now, calculate the final current (I2) using the final voltage.
Step 8: Substitute the final voltage and resistance into the formula: I2 = 15V / 5Ω.
Step 9: Calculate I2, which equals 3 A.
Step 10: Find the change in current by subtracting the initial current from the final current: Change in current = I2 - I1.
Step 11: Substitute the values: Change in current = 3 A - 1 A.
Step 12: Calculate the change in current, which equals 2 A.