What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in seri

What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

Correct Answer: 9Ω

Step 1: Identify the resistors you have. In this case, we have two resistors: one is 6Ω and the other is 3Ω.
Step 2: Understand that when resistors are connected in series, you add their resistances together.
Step 3: Write down the formula for equivalent resistance in series: R_eq = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_eq = 6Ω + 3Ω.
Step 5: Perform the addition: 6Ω + 3Ω = 9Ω.
Step 6: Conclude that the equivalent resistance of the two resistors in series is 9Ω.

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