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What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in seri
What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?
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Practice Questions
1 question
Q1
What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?
2Ω
3Ω
9Ω
18Ω
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In series, the equivalent resistance (R_eq) is the sum of the resistances: R_eq = 6Ω + 3Ω = 9Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?
Solution:
In series, the equivalent resistance (R_eq) is the sum of the resistances: R_eq = 6Ω + 3Ω = 9Ω.
Steps: 6
Show Steps
Step 1: Identify the resistors you have. In this case, we have two resistors: one is 6Ω and the other is 3Ω.
Step 2: Understand that when resistors are connected in series, you add their resistances together.
Step 3: Write down the formula for equivalent resistance in series: R_eq = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_eq = 6Ω + 3Ω.
Step 5: Perform the addition: 6Ω + 3Ω = 9Ω.
Step 6: Conclude that the equivalent resistance of the two resistors in series is 9Ω.
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