What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in seri

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Question: What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

Options:

Correct Answer: 9Ω

Solution:

In series, the equivalent resistance (R_eq) is the sum of the resistances: R_eq = 6Ω + 3Ω = 9Ω.

What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

Correct Answer: 9Ω

Step 1: Identify the resistors you have. In this case, we have two resistors: one is 6Ω and the other is 3Ω.
Step 2: Understand that when resistors are connected in series, you add their resistances together.
Step 3: Write down the formula for equivalent resistance in series: R_eq = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_eq = 6Ω + 3Ω.
Step 5: Perform the addition: 6Ω + 3Ω = 9Ω.
Step 6: Conclude that the equivalent resistance of the two resistors in series is 9Ω.

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