In a circuit with a 12V battery and two resistors in parallel (4 ohms and 6 ohms), what is the total current supplied by the battery?
Practice Questions
1 question
Q1
In a circuit with a 12V battery and two resistors in parallel (4 ohms and 6 ohms), what is the total current supplied by the battery?
3 A
2 A
1 A
4 A
First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 ohms. Then, using Ohm's law, I = V/R, we have I = 12V / 2.4 ohms = 5 A.
Questions & Step-by-step Solutions
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Q
Q: In a circuit with a 12V battery and two resistors in parallel (4 ohms and 6 ohms), what is the total current supplied by the battery?
Solution: First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 ohms. Then, using Ohm's law, I = V/R, we have I = 12V / 2.4 ohms = 5 A.
Steps: 10
Step 1: Identify the values given in the problem. We have a 12V battery and two resistors: one is 4 ohms and the other is 6 ohms.
Step 2: Use the formula for equivalent resistance in parallel circuits: 1/R_eq = 1/R1 + 1/R2. Here, R1 is 4 ohms and R2 is 6 ohms.
Step 3: Substitute the values into the formula: 1/R_eq = 1/4 + 1/6.
Step 4: Find a common denominator to add the fractions. The common denominator for 4 and 6 is 12.
Step 5: Rewrite the fractions: 1/4 = 3/12 and 1/6 = 2/12.
