Question: If two resistors of 4 ohms and 6 ohms are connected in series, what is the voltage drop across the 4 ohm resistor when a current of 2 A flows through the circuit?

Options:

1. 8 V
2. 4 V
3. 2 V
4. 6 V

Correct Answer: 8 V

Solution:

Using Ohm\'s law, V = I * R, the voltage drop across the 4 ohm resistor is V = 2 A * 4 ohms = 8 V.