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What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
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Practice Questions
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Q1
What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
12 W
9 W
6 W
3 W
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Using the power formula P = I^2 * R, we have P = (3 A)^2 * 4 ohms = 9 * 4 = 36 W.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
Solution:
Using the power formula P = I^2 * R, we have P = (3 A)^2 * 4 ohms = 9 * 4 = 36 W.
Steps: 6
Show Steps
Step 1: Identify the values given in the problem. We have a resistor with a resistance of 4 ohms and a current of 3 A.
Step 2: Write down the power formula. The formula to calculate power (P) is P = I^2 * R, where I is the current and R is the resistance.
Step 3: Substitute the values into the formula. Replace I with 3 A and R with 4 ohms: P = (3 A)^2 * 4 ohms.
Step 4: Calculate (3 A)^2. This means multiplying 3 A by itself: 3 A * 3 A = 9 A^2.
Step 5: Now multiply 9 A^2 by 4 ohms: 9 A^2 * 4 ohms = 36 W.
Step 6: The final answer is that the power dissipated in the resistor is 36 watts.
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