In a circuit with three resistors in series (2 ohms, 3 ohms, and 5 ohms), what i

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Question: In a circuit with three resistors in series (2 ohms, 3 ohms, and 5 ohms), what is the total resistance?

Options:

Correct Answer: 10 ohms

Solution:

For resistors in series, R_total = R1 + R2 + R3 = 2 + 3 + 5 = 10 ohms.

In a circuit with three resistors in series (2 ohms, 3 ohms, and 5 ohms), what is the total resistance?

In a circuit with three resistors in series (2 ohms, 3 ohms, and 5 ohms), what is the total resistance?

Correct Answer: 10 ohms

Step 1: Identify the resistors in the circuit. We have three resistors: 2 ohms, 3 ohms, and 5 ohms.
Step 2: Understand that when resistors are in series, you add their resistances together to find the total resistance.
Step 3: Write down the formula for total resistance in series: R_total = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R_total = 2 ohms + 3 ohms + 5 ohms.
Step 5: Perform the addition: 2 + 3 = 5, then 5 + 5 = 10.
Step 6: Conclude that the total resistance of the circuit is 10 ohms.

Series Resistors – In a series circuit, the total resistance is the sum of the individual resistances.