Evaluate the integral ∫(2x + 3) dx from 1 to 2.

Practice Questions

Q1
Evaluate the integral ∫(2x + 3) dx from 1 to 2.
  1. 8
  2. 7
  3. 6
  4. 5

Questions & Step-by-Step Solutions

Evaluate the integral ∫(2x + 3) dx from 1 to 2.
  • Step 1: Identify the function to integrate, which is (2x + 3).
  • Step 2: Find the antiderivative of the function. The antiderivative of 2x is x^2, and the antiderivative of 3 is 3x. So, the antiderivative of (2x + 3) is x^2 + 3x.
  • Step 3: Write the definite integral using the antiderivative. We need to evaluate [x^2 + 3x] from 1 to 2.
  • Step 4: Substitute the upper limit (2) into the antiderivative: (2^2 + 3*2) = (4 + 6) = 10.
  • Step 5: Substitute the lower limit (1) into the antiderivative: (1^2 + 3*1) = (1 + 3) = 4.
  • Step 6: Subtract the result of the lower limit from the result of the upper limit: 10 - 4 = 6.
  • Definite Integral – The process of calculating the area under a curve defined by a function over a specific interval.
  • Fundamental Theorem of Calculus – Relates differentiation and integration, allowing the evaluation of definite integrals using antiderivatives.
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