In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is t

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Question: In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the current flowing through the circuit?

Options:

Correct Answer: 2A

Solution:

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω; I = V / R = 12V / 12Ω = 1A.

In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the current flowing through the circuit?

In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the current flowing through the circuit?

Correct Answer: 1A

Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the resistors in the circuit, which are 4Ω and 8Ω.
Step 3: Calculate the total resistance in the series circuit by adding the resistances together: R = R1 + R2 = 4Ω + 8Ω.
Step 4: Perform the addition: 4Ω + 8Ω = 12Ω.
Step 5: Use Ohm's Law to find the current: I = V / R.
Step 6: Substitute the values into the formula: I = 12V / 12Ω.
Step 7: Perform the division: 12V / 12Ω = 1A.
Step 8: Conclude that the current flowing through the circuit is 1A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as I = V / R.
Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
Total Resistance in Series – In a series circuit, the total resistance is the sum of the individual resistances.