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In a certain division problem, if the dividend is 37 and the divisor is 5, what
In a certain division problem, if the dividend is 37 and the divisor is 5, what is the remainder? (2023)
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In a certain division problem, if the dividend is 37 and the divisor is 5, what is the remainder? (2023)
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When 37 is divided by 5, it goes 7 times (7*5=35) with a remainder of 2 (37-35=2).
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Q
Q: In a certain division problem, if the dividend is 37 and the divisor is 5, what is the remainder? (2023)
Solution:
When 37 is divided by 5, it goes 7 times (7*5=35) with a remainder of 2 (37-35=2).
Steps: 5
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Step 1: Identify the dividend and the divisor. The dividend is 37 and the divisor is 5.
Step 2: Determine how many times 5 can fit into 37 without exceeding it. 5 goes into 37 a total of 7 times.
Step 3: Multiply the divisor (5) by the number of times it fits (7). This gives you 5 * 7 = 35.
Step 4: Subtract the result from the dividend. So, 37 - 35 = 2.
Step 5: The result from Step 4 is the remainder. Therefore, the remainder is 2.
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