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In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

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Question: In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?

Options:

  1. 2A
  2. 4A
  3. 6A
  4. 8A

Correct Answer: 4A

Solution: 

Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

Practice Questions

Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?
  1. 2A
  2. 4A
  3. 6A
  4. 8A

Questions & Step-by-Step Solutions

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?
Correct Answer: 6A
  • Step 1: Identify the values given in the problem. We have two resistors: one is 6Ω and the other is 3Ω. The voltage across them is 12V.
  • Step 2: Calculate the equivalent resistance (Req) of the two resistors in parallel using the formula: 1/Req = 1/R1 + 1/R2.
  • Step 3: Substitute the values of the resistors into the formula: 1/Req = 1/6 + 1/3.
  • Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6. So, 1/3 can be rewritten as 2/6.
  • Step 5: Now add the fractions: 1/Req = 1/6 + 2/6 = 3/6.
  • Step 6: Simplify the fraction: 3/6 = 1/2. Therefore, Req = 2Ω (by taking the reciprocal).
  • Step 7: Now, use Ohm's law to find the total current (I) flowing through the circuit. The formula is I = V / Req.
  • Step 8: Substitute the values into the formula: I = 12V / 2Ω.
  • Step 9: Calculate the total current: I = 6A.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Resistors in Parallel – The total resistance (Req) of resistors in parallel is found using the formula 1/Req = 1/R1 + 1/R2, which results in a lower total resistance than any individual resistor.
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