In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?
Practice Questions
1 question
Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?
2A
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Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?
Solution: Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.
Steps: 9
Step 1: Identify the values given in the problem. We have two resistors: one is 6Ω and the other is 3Ω. The voltage across them is 12V.
Step 2: Calculate the equivalent resistance (Req) of the two resistors in parallel using the formula: 1/Req = 1/R1 + 1/R2.
Step 3: Substitute the values of the resistors into the formula: 1/Req = 1/6 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6. So, 1/3 can be rewritten as 2/6.
Step 5: Now add the fractions: 1/Req = 1/6 + 2/6 = 3/6.
Step 6: Simplify the fraction: 3/6 = 1/2. Therefore, Req = 2Ω (by taking the reciprocal).
Step 7: Now, use Ohm's law to find the total current (I) flowing through the circuit. The formula is I = V / Req.
Step 8: Substitute the values into the formula: I = 12V / 2Ω.
