In a number system where 'A' represents 10, 'B' represents 11, and 'C' represent

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Question: In a number system where \'A\' represents 10, \'B\' represents 11, and \'C\' represents 12, what is the decimal equivalent of \'BAC\'?

Options:

Correct Answer: 187

Solution:

\'BAC\' = 11*16^2 + 10*16^1 + 12*16^0 = 186 + 10 + 12 = 188.

In a number system where 'A' represents 10, 'B' represents 11, and 'C' represents 12, what is the decimal equivalent of 'BAC'?

In a number system where 'A' represents 10, 'B' represents 11, and 'C' represents 12, what is the decimal equivalent of 'BAC'?

Step 1: Identify the values of each character in 'BAC'. 'B' is 11, 'A' is 10, and 'C' is 12.
Step 2: Determine the position of each character. 'B' is in the 16^2 position, 'A' is in the 16^1 position, and 'C' is in the 16^0 position.
Step 3: Calculate the value of 'B' in decimal: 11 * 16^2 = 11 * 256 = 2816.
Step 4: Calculate the value of 'A' in decimal: 10 * 16^1 = 10 * 16 = 160.
Step 5: Calculate the value of 'C' in decimal: 12 * 16^0 = 12 * 1 = 12.
Step 6: Add all the values together: 2816 + 160 + 12 = 2990.
Step 7: The decimal equivalent of 'BAC' is 2990.

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