In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω)

In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) in parallel, what is the total current supplied by the battery?

In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) in parallel, what is the total current supplied by the battery?

Correct Answer: 18A

Step 1: Identify the values given in the problem. We have a 24V battery and three resistors, each with a resistance of 4Ω (R1, R2, R3).
Step 2: Since the resistors are in parallel, we need to find the equivalent resistance (R_eq) using the formula: R_eq = 1 / (1/R1 + 1/R2 + 1/R3).
Step 3: Substitute the values of the resistors into the formula: R_eq = 1 / (1/4 + 1/4 + 1/4).
Step 4: Calculate the sum inside the parentheses: 1/4 + 1/4 + 1/4 = 3/4.
Step 5: Now, take the reciprocal of 3/4: R_eq = 1 / (3/4) = 4/3 = 1.33Ω.
Step 6: Now that we have the equivalent resistance, we can find the total current (I) supplied by the battery using Ohm's Law: I = V / R_eq.
Step 7: Substitute the values into the formula: I = 24V / 1.33Ω.
Step 8: Calculate the total current: I ≈ 18A.

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