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What is the power dissipated in a resistor of 5Ω carrying a current of 3A?

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Question: What is the power dissipated in a resistor of 5Ω carrying a current of 3A?

Options:

  1. 15W
  2. 9W
  3. 5W
  4. 3W

Correct Answer: 15W

Solution: 

Power P = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.

What is the power dissipated in a resistor of 5Ω carrying a current of 3A?

Practice Questions

Q1
What is the power dissipated in a resistor of 5Ω carrying a current of 3A?
  1. 15W
  2. 9W
  3. 5W
  4. 3W

Questions & Step-by-Step Solutions

What is the power dissipated in a resistor of 5Ω carrying a current of 3A?
Correct Answer: 45W
  • Step 1: Identify the values given in the problem. We have a resistor with a resistance of 5 ohms (Ω) and a current of 3 amperes (A).
  • Step 2: Recall the formula for power (P) in a resistor, which is P = I^2 * R, where I is the current and R is the resistance.
  • Step 3: Substitute the values into the formula. Here, I = 3A and R = 5Ω.
  • Step 4: Calculate I^2. This means multiplying the current by itself: (3A) * (3A) = 9A^2.
  • Step 5: Now multiply the result from Step 4 by the resistance. So, we take 9A^2 and multiply it by 5Ω: 9A^2 * 5Ω = 45W.
  • Step 6: The final answer is that the power dissipated in the resistor is 45 watts (W).
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