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In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the t
In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?
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Practice Questions
1 question
Q1
In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?
2Ω
4Ω
6Ω
10Ω
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The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?
Solution:
The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.
Steps: 6
Show Steps
Step 1: Identify the values of the resistors. Here, R1 is 4Ω and R2 is 6Ω.
Step 2: Understand that when resistors are in series, you add their resistances together.
Step 3: Write the formula for total resistance in series: R_total = R1 + R2.
Step 4: Substitute the values into the formula: R_total = 4Ω + 6Ω.
Step 5: Perform the addition: 4Ω + 6Ω = 10Ω.
Step 6: Conclude that the total resistance is 10Ω.
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