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In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the t

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Question: In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?

Options:

  1. 2Ω
  2. 4Ω
  3. 6Ω
  4. 10Ω

Correct Answer: 10Ω

Solution: 

The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.

In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the t

Practice Questions

Q1
In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?
  1. 2Ω
  2. 4Ω
  3. 6Ω
  4. 10Ω

Questions & Step-by-Step Solutions

In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?
Correct Answer: 10Ω
  • Step 1: Identify the values of the resistors. Here, R1 is 4Ω and R2 is 6Ω.
  • Step 2: Understand that when resistors are in series, you add their resistances together.
  • Step 3: Write the formula for total resistance in series: R_total = R1 + R2.
  • Step 4: Substitute the values into the formula: R_total = 4Ω + 6Ω.
  • Step 5: Perform the addition: 4Ω + 6Ω = 10Ω.
  • Step 6: Conclude that the total resistance is 10Ω.
  • Series Resistance Calculation – In a series circuit, the total resistance is the sum of the individual resistances.
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