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If a circuit has a 15V battery and two resistors (5Ω and 10Ω) in series, what is
If a circuit has a 15V battery and two resistors (5Ω and 10Ω) in series, what is the voltage across the 10Ω resistor?
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Practice Questions
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Q1
If a circuit has a 15V battery and two resistors (5Ω and 10Ω) in series, what is the voltage across the 10Ω resistor?
5V
10V
15V
0V
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Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.
Questions & Step-by-step Solutions
1 item
Q
Q: If a circuit has a 15V battery and two resistors (5Ω and 10Ω) in series, what is the voltage across the 10Ω resistor?
Solution:
Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.
Steps: 6
Show Steps
Step 1: Identify the total voltage from the battery, which is 15V.
Step 2: Identify the resistors in the circuit. We have R1 = 5Ω and R2 = 10Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors together: Rtotal = R1 + R2 = 5Ω + 10Ω = 15Ω.
Step 4: Use the voltage divider rule to find the voltage across the 10Ω resistor (R2). The formula is V2 = (R2 / Rtotal) * Vtotal.
Step 5: Substitute the values into the formula: V2 = (10Ω / 15Ω) * 15V.
Step 6: Simplify the calculation: V2 = (10 / 15) * 15 = 10V.
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