What is the total current in a circuit with a 24V battery and three resistors (2Ω, 4Ω, and 6Ω) connected in series?

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Q: What is the total current in a circuit with a 24V battery and three resistors (2Ω, 4Ω, and 6Ω) connected in series?

Solution: Total resistance R = R1 + R2 + R3 = 2Ω + 4Ω + 6Ω = 12Ω. Using Ohm's law, I = V/R = 24V / 12Ω = 2A.

Steps: 7

Step 1: Identify the values given in the problem. We have a 24V battery and three resistors with values 2Ω, 4Ω, and 6Ω.
Step 2: Understand that the resistors are connected in series. This means we need to add their resistances together to find the total resistance.
Step 3: Calculate the total resistance (R) by adding the values of the resistors: R = R1 + R2 + R3 = 2Ω + 4Ω + 6Ω.
Step 4: Perform the addition: 2 + 4 + 6 = 12Ω. So, the total resistance is 12Ω.
Step 5: Use Ohm's Law to find the current (I). Ohm's Law states that I = V / R, where V is voltage and R is resistance.
Step 6: Substitute the values into the formula: I = 24V / 12Ω.
Step 7: Perform the division: 24 / 12 = 2A. So, the total current in the circuit is 2A.