If the area of a trapezium is 60 square units and the lengths of the parallel si

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Question: If the area of a trapezium is 60 square units and the lengths of the parallel sides are 10 units and 20 units, what is the height?

Options:

Correct Answer: 6 units

Solution:

Area = (1/2) × (base1 + base2) × height. Thus, 60 = (1/2) × (10 + 20) × height, giving height = 60 / 15 = 4 units.

If the area of a trapezium is 60 square units and the lengths of the parallel sides are 10 units and 20 units, what is the height?

If the area of a trapezium is 60 square units and the lengths of the parallel sides are 10 units and 20 units, what is the height?

Step 1: Write down the formula for the area of a trapezium: Area = (1/2) × (base1 + base2) × height.
Step 2: Identify the values given in the question: Area = 60 square units, base1 = 10 units, base2 = 20 units.
Step 3: Substitute the values into the formula: 60 = (1/2) × (10 + 20) × height.
Step 4: Calculate the sum of the bases: 10 + 20 = 30.
Step 5: Substitute the sum back into the equation: 60 = (1/2) × 30 × height.
Step 6: Simplify (1/2) × 30 to get 15: 60 = 15 × height.
Step 7: To find the height, divide both sides by 15: height = 60 / 15.
Step 8: Calculate the division: height = 4 units.

Area of a Trapezium – The formula for the area of a trapezium involves the lengths of the two parallel sides and the height.
Algebraic Manipulation – The ability to rearrange the area formula to solve for the height.