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Using Kirchhoff's voltage law, if a loop in a circuit has a 9V battery and two r

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Question: Using Kirchhoff\'s voltage law, if a loop in a circuit has a 9V battery and two resistors (2Ω and 3Ω) with voltage drops of 4V and 5V respectively, is the loop correctly analyzed?

Options:

  1. Yes
  2. No
  3. Only if the battery is 12V
  4. Only if the resistors are in series

Correct Answer: No

Solution: 

According to Kirchhoff\'s voltage law, the sum of the voltage drops must equal the source voltage. Here, 4V + 5V = 9V, which is correct.

Using Kirchhoff's voltage law, if a loop in a circuit has a 9V battery and two r

Practice Questions

Q1
Using Kirchhoff's voltage law, if a loop in a circuit has a 9V battery and two resistors (2Ω and 3Ω) with voltage drops of 4V and 5V respectively, is the loop correctly analyzed?
  1. Yes
  2. No
  3. Only if the battery is 12V
  4. Only if the resistors are in series

Questions & Step-by-Step Solutions

Using Kirchhoff's voltage law, if a loop in a circuit has a 9V battery and two resistors (2Ω and 3Ω) with voltage drops of 4V and 5V respectively, is the loop correctly analyzed?
Correct Answer: Yes, the loop is correctly analyzed.
  • Step 1: Identify the components in the loop: a 9V battery, a 2Ω resistor, and a 3Ω resistor.
  • Step 2: Note the voltage drops across the resistors: 4V for the 2Ω resistor and 5V for the 3Ω resistor.
  • Step 3: According to Kirchhoff's voltage law, add the voltage drops together: 4V + 5V.
  • Step 4: Calculate the total voltage drop: 4V + 5V = 9V.
  • Step 5: Compare the total voltage drop (9V) to the voltage of the battery (9V).
  • Step 6: Since the total voltage drop equals the battery voltage, the loop is correctly analyzed.
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