If a wire carries a current of 4 A and has a resistance of 2 ohms, what is the p

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Question: If a wire carries a current of 4 A and has a resistance of 2 ohms, what is the power dissipated in the wire?

Options:

Correct Answer: 16 W

Solution:

Power (P) is given by P = I^2 * R. Thus, P = (4 A)^2 * 2 Ω = 16 W.

If a wire carries a current of 4 A and has a resistance of 2 ohms, what is the power dissipated in the wire?

If a wire carries a current of 4 A and has a resistance of 2 ohms, what is the power dissipated in the wire?

Step 1: Identify the current (I) flowing through the wire, which is given as 4 A.
Step 2: Identify the resistance (R) of the wire, which is given as 2 ohms.
Step 3: Use the formula for power (P) which is P = I^2 * R.
Step 4: Substitute the values into the formula: P = (4 A)^2 * 2 Ω.
Step 5: Calculate (4 A)^2, which is 16 A^2.
Step 6: Multiply 16 A^2 by 2 Ω to find the power: 16 A^2 * 2 Ω = 32 W.
Step 7: Conclude that the power dissipated in the wire is 32 W.

Ohm's Law and Power Calculation – Understanding the relationship between current, resistance, and power dissipation in electrical circuits.