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What is the magnetic field strength at the center of a circular loop of radius 0

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Question: What is the magnetic field strength at the center of a circular loop of radius 0.1 m carrying a current of 3 A?

Options:

  1. 0.03 T
  2. 0.1 T
  3. 0.15 T
  4. 0.2 T

Correct Answer: 0.1 T

Solution:

The magnetic field (B) at the center of a circular loop is given by B = (μ₀ * I) / (2 * R). Using μ₀ = 4π x 10^-7 Tm/A, B = (4π x 10^-7 * 3) / (2 * 0.1) = 0.1 T.

What is the magnetic field strength at the center of a circular loop of radius 0

Practice Questions

Q1
What is the magnetic field strength at the center of a circular loop of radius 0.1 m carrying a current of 3 A?
  1. 0.03 T
  2. 0.1 T
  3. 0.15 T
  4. 0.2 T

Questions & Step-by-Step Solutions

What is the magnetic field strength at the center of a circular loop of radius 0.1 m carrying a current of 3 A?
  • Step 1: Identify the formula for the magnetic field (B) at the center of a circular loop. The formula is B = (μ₀ * I) / (2 * R).
  • Step 2: Identify the values needed for the formula. Here, μ₀ (the permeability of free space) is 4Ï€ x 10^-7 Tm/A, I (the current) is 3 A, and R (the radius) is 0.1 m.
  • Step 3: Substitute the values into the formula. B = (4Ï€ x 10^-7 * 3) / (2 * 0.1).
  • Step 4: Calculate the denominator. 2 * 0.1 = 0.2.
  • Step 5: Calculate the numerator. 4Ï€ x 10^-7 * 3 = 12Ï€ x 10^-7.
  • Step 6: Now divide the numerator by the denominator. B = (12Ï€ x 10^-7) / 0.2.
  • Step 7: Simplify the division. B = 60Ï€ x 10^-7 T.
  • Step 8: Calculate the numerical value. Using Ï€ ≈ 3.14, B ≈ 60 * 3.14 x 10^-7 = 188.4 x 10^-7 T = 0.1 T.
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