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A spring has a spring constant of 200 N/m. How much force is required to stretch
A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.5 m?
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Q1
A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.5 m?
50 N
100 N
150 N
200 N
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Using Hooke's law, F = kx = 200 N/m * 0.5 m = 100 N.
Questions & Step-by-step Solutions
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Q
Q: A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.5 m?
Solution:
Using Hooke's law, F = kx = 200 N/m * 0.5 m = 100 N.
Steps: 5
Show Steps
Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the distance the spring is stretched (x). Here, x = 0.5 m.
Step 3: Use Hooke's law formula, which is F = k * x.
Step 4: Substitute the values into the formula: F = 200 N/m * 0.5 m.
Step 5: Calculate the force: F = 100 N.
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