If a mixture contains 20% alcohol and 80% water, how much alcohol is present in

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Question: If a mixture contains 20% alcohol and 80% water, how much alcohol is present in 50 liters of the mixture?

Options:

Correct Answer: 10 liters

Solution:

20% of 50 liters = 0.2 * 50 = 10 liters of alcohol.

If a mixture contains 20% alcohol and 80% water, how much alcohol is present in 50 liters of the mixture?

If a mixture contains 20% alcohol and 80% water, how much alcohol is present in 50 liters of the mixture?

Step 1: Understand that the mixture is made up of 20% alcohol and 80% water.
Step 2: Know that 20% means 20 out of every 100 parts of the mixture is alcohol.
Step 3: We need to find out how much alcohol is in 50 liters of this mixture.
Step 4: To find 20% of 50 liters, we can use the formula: (percentage / 100) * total amount.
Step 5: Plug in the numbers: (20 / 100) * 50.
Step 6: Calculate 20 / 100, which equals 0.2.
Step 7: Now multiply 0.2 by 50 liters: 0.2 * 50 = 10 liters.
Step 8: Therefore, there are 10 liters of alcohol in the 50 liters of mixture.

Percentage Calculation – Understanding how to calculate a percentage of a total quantity.
Mixture Composition – Recognizing the components of a mixture and their respective proportions.