Question: If the first term of a geometric progression is x and the common ratio is 1/2, what is the sum of the first 5 terms?
Options:
Correct Answer: x(1 - (1/2)^5)/(1 - 1/2)
Solution:
The sum of the first n terms of a GP is given by S_n = a(1 - r^n) / (1 - r). Here, S_5 = x(1 - (1/2)^5) / (1 - 1/2) = x(1 - 1/32) / (1/2) = x(31/32) * 2 = x(62/32).