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In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parall
In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?
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Practice Questions
1 question
Q1
In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?
2Ω
3Ω
5Ω
10Ω
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1/R_eq = 1/5 + 1/10 + 1/15 = 0.1 + 0.0667 + 0.0667 = 0.2334. Therefore, R_eq = 4.29Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?
Solution:
1/R_eq = 1/5 + 1/10 + 1/15 = 0.1 + 0.0667 + 0.0667 = 0.2334. Therefore, R_eq = 4.29Ω.
Steps: 7
Show Steps
Step 1: Identify the resistors in the circuit. We have three resistors: 5Ω, 10Ω, and 15Ω.
Step 2: Write down the formula for equivalent resistance (R_eq) for resistors in parallel: 1/R_eq = 1/R1 + 1/R2 + 1/R3.
Step 3: Substitute the values of the resistors into the formula: 1/R_eq = 1/5 + 1/10 + 1/15.
Step 4: Calculate each term separately: 1/5 = 0.2, 1/10 = 0.1, and 1/15 = 0.0667.
Step 5: Add the results together: 0.2 + 0.1 + 0.0667 = 0.3667.
Step 6: Now, take the reciprocal to find R_eq: R_eq = 1 / 0.3667.
Step 7: Calculate the final value: R_eq ≈ 2.73Ω.
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