If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?
Practice Questions
1 question
Q1
If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?
4 V
8 V
6 V
12 V
The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.
Questions & Step-by-step Solutions
1 item
Q
Q: If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?
Solution: The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.
Steps: 3
Step 1: Identify the total resistance in the circuit. Add the resistance of the two resistors together: 4 ohms + 8 ohms = 12 ohms.
Step 2: Use Ohm's Law to find the current in the circuit. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R). Here, V is 12V and R is 12 ohms. So, I = 12V / 12 ohms = 1 A.
Step 3: Calculate the voltage across the 8 ohm resistor. Use the formula V = I * R, where I is the current (1 A) and R is the resistance of the 8 ohm resistor. So, V = 1 A * 8 ohms = 8 V.
