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If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series,

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Question: If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?

Options:

  1. 4 V
  2. 8 V
  3. 6 V
  4. 12 V

Correct Answer: 8 V

Solution: 

The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.

If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series,

Practice Questions

Q1
If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?
  1. 4 V
  2. 8 V
  3. 6 V
  4. 12 V

Questions & Step-by-Step Solutions

If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?
Correct Answer: 8 V
  • Step 1: Identify the total resistance in the circuit. Add the resistance of the two resistors together: 4 ohms + 8 ohms = 12 ohms.
  • Step 2: Use Ohm's Law to find the current in the circuit. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R). Here, V is 12V and R is 12 ohms. So, I = 12V / 12 ohms = 1 A.
  • Step 3: Calculate the voltage across the 8 ohm resistor. Use the formula V = I * R, where I is the current (1 A) and R is the resistance of the 8 ohm resistor. So, V = 1 A * 8 ohms = 8 V.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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