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What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
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Q1
What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
20 W
10 W
5 W
40 W
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Using the power formula P = I^2 * R, we have P = (2 A)^2 * 10 ohms = 4 * 10 = 40 W.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
Solution:
Using the power formula P = I^2 * R, we have P = (2 A)^2 * 10 ohms = 4 * 10 = 40 W.
Steps: 6
Show Steps
Step 1: Identify the values given in the problem. We have a resistor with a resistance of 10 ohms and a current of 2 A.
Step 2: Write down the power formula. The formula to calculate power (P) in a resistor is P = I^2 * R, where I is the current and R is the resistance.
Step 3: Substitute the values into the formula. Replace I with 2 A and R with 10 ohms: P = (2 A)^2 * 10 ohms.
Step 4: Calculate (2 A)^2. This means 2 A multiplied by itself, which equals 4 A^2.
Step 5: Multiply the result by the resistance. Now multiply 4 A^2 by 10 ohms: 4 * 10 = 40.
Step 6: State the final answer. The power dissipated in the resistor is 40 watts (W).
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