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In a circuit with two resistors in series, if the total resistance is 12 ohms an

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Question: In a circuit with two resistors in series, if the total resistance is 12 ohms and one resistor is 4 ohms, what is the value of the other resistor?

Options:

  1. 8 ohms
  2. 4 ohms
  3. 12 ohms
  4. 16 ohms

Correct Answer: 8 ohms

Solution: 

Using the formula for resistors in series, R_total = R1 + R2, we have 12 = 4 + R2, thus R2 = 12 - 4 = 8 ohms.

In a circuit with two resistors in series, if the total resistance is 12 ohms an

Practice Questions

Q1
In a circuit with two resistors in series, if the total resistance is 12 ohms and one resistor is 4 ohms, what is the value of the other resistor?
  1. 8 ohms
  2. 4 ohms
  3. 12 ohms
  4. 16 ohms

Questions & Step-by-Step Solutions

In a circuit with two resistors in series, if the total resistance is 12 ohms and one resistor is 4 ohms, what is the value of the other resistor?
Correct Answer: 8 ohms
  • Step 1: Understand that in a series circuit, the total resistance is the sum of the individual resistances.
  • Step 2: Write down the formula for total resistance in series: R_total = R1 + R2.
  • Step 3: Identify the values given in the problem: R_total is 12 ohms and R1 (the first resistor) is 4 ohms.
  • Step 4: Substitute the known values into the formula: 12 = 4 + R2.
  • Step 5: To find R2, rearrange the equation: R2 = 12 - 4.
  • Step 6: Calculate R2: R2 = 8 ohms.
  • Resistors in Series – In a series circuit, the total resistance is the sum of the individual resistances.
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