In a circuit with two resistors in series, if the total resistance is 12 ohms and one resistor is 4 ohms, what is the value of the other resistor?

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Q: In a circuit with two resistors in series, if the total resistance is 12 ohms and one resistor is 4 ohms, what is the value of the other resistor?

Solution: Using the formula for resistors in series, R_total = R1 + R2, we have 12 = 4 + R2, thus R2 = 12 - 4 = 8 ohms.

Steps: 6

Step 1: Understand that in a series circuit, the total resistance is the sum of the individual resistances.
Step 2: Write down the formula for total resistance in series: R_total = R1 + R2.
Step 3: Identify the values given in the problem: R_total is 12 ohms and R1 (the first resistor) is 4 ohms.
Step 4: Substitute the known values into the formula: 12 = 4 + R2.
Step 5: To find R2, rearrange the equation: R2 = 12 - 4.
Step 6: Calculate R2: R2 = 8 ohms.